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7votes
2answers
313views

Tree-level of two-point function

I am currently learning AQFT (advanced QFT) with the lecture notes of Osborn (I've had a course on QFT but this was not with the path integral formalism) and at some point he says the following $$\...
RoITF73's user avatar
1vote
1answer
89views

Performing the shift in the Dirac generating functional to complete the square

I'm following Peskin & Schroeder p.302, and am trying to show that the generating functional for the Dirac field can be written as $$ Z\left[\bar{\eta}, \eta\right] = Z_0 \exp \left[-\int d^4 x d^...
chrv's user avatar
1vote
1answer
262views

The path integral for $\phi^3$ theory solved explicitly in terms of Feynman diagrams

I'm currently working through Srednicki's book on QFT and I try to better understand the path integral and the Feynman diagrams. Equation 9.11 reads $$\begin{align}Z_1(J) \propto& \sum_V\frac{1}{V!...
onionring's user avatar
1vote
0answers
62views

Time translation invariance of the two-point function

Please refer to this 2023 lecture note by Douglas Ross. In this note, they compute the generating functional for the correlators given by Eq (4.7) for a harmonic oscillator action. $$\begin{aligned} &...
Dr. user44690's user avatar
2votes
1answer
103views

What is the physical meaning of the normalization of the propagator in quantum mechanics?

Suppose we have a quantum field theory (QFT) for a scalar field $\phi$ with vacuum state $|\Omega\rangle$. Then, in units where $\hbar = 1$, we postulate that the vacuum expectation value (VEV) of any ...
zeroknowledgeprover's user avatar
0votes
1answer
72views

Why isn't the free particle particle a function of the absolute value of the difference of the time?

The one-dimensional free particle Lagrangian is given by $$ \mathcal{L} = \frac{m}{2}\dot x^2. $$ Since the Lagrangian is translation-invariant, one usually argues that the propagator can only be a ...
zeroknowledgeprover's user avatar
2votes
2answers
219views

Time ordering for a time-dependent Hamiltonian in Path integral derivation

I am currently taking a class on Quantum Field Theory. The propagator was defined as: $$K(x,t;x',t') = \langle x|\hat{T}e^{{\frac{-i}{\hbar}\int_{t}^{t'}dtH(t)}}|x\rangle$$ where, $\hat{T}$ is the ...
ofbrakets's user avatar
2votes
1answer
130views

The definition on vacuum-vacuum amplitude with current in chapter of External Field Method of Weinberg's QFT

I'm reading Vol. 2 of Weinberg's QFT. As what I learnt from both P&S and Weinberg, the generating function is defined as $$ Z[J] = \int \mathcal{D}\phi \exp(iS_{\text{F}}[\phi] + i\int d^4x\phi(x) ...
LaplaceSpell's user avatar
1vote
1answer
59views

Fermionic propagator [closed]

Given the fermionic generating functional $$Z[\eta]=\ det^{\frac{1}{2}}(K_{ij})e^{-\frac{i}{2}\eta_{i}G^{ij}\eta_{j}},\tag{1}$$ where $$G^{ij}=K^{-1}_{ij}$$ is the Green function of our theory, then ...
Michael 's user avatar
1vote
0answers
160views

Derivation of massive photon propagator

I'm trying to derive the massive photon propagator using the path integral formalism for a theory with $$ \mathcal{L} = -\dfrac{1}{4} F_{\mu\nu} F^{\mu\nu} + \dfrac{1}{2} m^2 A_\mu A^\nu, \text{with } ...
Gabriel Ybarra Marcaida's user avatar
1vote
1answer
90views

Time ordered correlator from path integral: equation of motion?

Consider a Lagrangian $L(\phi)$ for a field $\phi$ (assume it is a free real scalar for simplicity). Then the time ordered propagator can be expressed as a path integral $$ \langle\Omega|T\{ \phi(x) \...
QuantumEyedea's user avatar
2votes
1answer
413views

Physical interpretation of photon propagator

Physically, propagator represents the probability amplitude of a particle to travel from one point to another. But the photon propagator $$D_{\mu\nu}(x,y) = \langle 0 | \mathcal{T}[A_\mu(x) A_\nu(y)] ...
FieldTheorist's user avatar
1vote
1answer
280views

Application of Cauchy residue theorem to Matsubara sums

For reference, this derivation is closely related to the discussion on pp. 169-173 of Altland and Simons. In quantum field theory (specifically when calculating free fermionic propagators via coherent ...
Jamin's user avatar
2votes
1answer
131views

Why must the propagator exponent be imaginary?

In response to asmaier's question, qmechanic showed why the propagator must be $\exp(cS)$. That made perfect sense. But can it also be shown that $c$ is imaginary? I believe it follows from ...
JoeJeffrey's user avatar
0votes
1answer
595views

How is the free particle propagator derived? [closed]

The free particle propagator is a well known function, for example, see Wikipedia. However, I cannot find a source that explains how to derive the free particle propagator. Please explain how the free ...
ipie's user avatar
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